-.016x^2+.5x+4.5=0

Solution for -.016x^2+.5x+4.5=0 equation:

-.016x^2+.5x+4.5=0

We add all the numbers together, and all the variables

-0.016x^2+.5x+4.5=0

a = -0.016; b = .5; c = +4.5;
Δ = b2-4ac
Δ = .52-4·(-0.016)·4.5
Δ = 0.538
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.5)-\sqrt{0.538}}{2*-0.016}=\frac{-0.5-\sqrt{0.538}}{-0.032}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.5)+\sqrt{0.538}}{2*-0.016}=\frac{-0.5+\sqrt{0.538}}{-0.032}
$